10v^2-8v-18=-10

Solution for 10v^2-8v-18=-10 equation:

10v^2-8v-18=-10

We move all terms to the left:

10v^2-8v-18-(-10)=0

We add all the numbers together, and all the variables

10v^2-8v-8=0

a = 10; b = -8; c = -8;
Δ = b2-4ac
Δ = -82-4·10·(-8)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8\sqrt{6}}{2*10}=\frac{8-8\sqrt{6}}{20}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8\sqrt{6}}{2*10}=\frac{8+8\sqrt{6}}{20}
$